Integrand size = 25, antiderivative size = 117 \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\frac {a (a+4 b) \text {arctanh}\left (\frac {\sqrt {b} \sin (e+f x)}{\sqrt {a+b \sin ^2(e+f x)}}\right )}{8 b^{3/2} f}+\frac {(a+4 b) \sin (e+f x) \sqrt {a+b \sin ^2(e+f x)}}{8 b f}-\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f} \]
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Time = 0.18 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {3269, 396, 201, 223, 212} \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\frac {a (a+4 b) \text {arctanh}\left (\frac {\sqrt {b} \sin (e+f x)}{\sqrt {a+b \sin ^2(e+f x)}}\right )}{8 b^{3/2} f}-\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f}+\frac {(a+4 b) \sin (e+f x) \sqrt {a+b \sin ^2(e+f x)}}{8 b f} \]
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Rule 201
Rule 212
Rule 223
Rule 396
Rule 3269
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \left (1-x^2\right ) \sqrt {a+b x^2} \, dx,x,\sin (e+f x)\right )}{f} \\ & = -\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f}+\frac {(a+4 b) \text {Subst}\left (\int \sqrt {a+b x^2} \, dx,x,\sin (e+f x)\right )}{4 b f} \\ & = \frac {(a+4 b) \sin (e+f x) \sqrt {a+b \sin ^2(e+f x)}}{8 b f}-\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f}+\frac {(a (a+4 b)) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,\sin (e+f x)\right )}{8 b f} \\ & = \frac {(a+4 b) \sin (e+f x) \sqrt {a+b \sin ^2(e+f x)}}{8 b f}-\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f}+\frac {(a (a+4 b)) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sin (e+f x)}{\sqrt {a+b \sin ^2(e+f x)}}\right )}{8 b f} \\ & = \frac {a (a+4 b) \text {arctanh}\left (\frac {\sqrt {b} \sin (e+f x)}{\sqrt {a+b \sin ^2(e+f x)}}\right )}{8 b^{3/2} f}+\frac {(a+4 b) \sin (e+f x) \sqrt {a+b \sin ^2(e+f x)}}{8 b f}-\frac {\sin (e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 b f} \\ \end{align*}
Time = 0.47 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.07 \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\frac {\sqrt {a+b \sin ^2(e+f x)} \left (\sqrt {a} (a+4 b) \text {arcsinh}\left (\frac {\sqrt {b} \sin (e+f x)}{\sqrt {a}}\right )-\sqrt {b} \sin (e+f x) \left (a-4 b+2 b \sin ^2(e+f x)\right ) \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}\right )}{8 b^{3/2} f \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}} \]
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Time = 0.58 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.25
method | result | size |
derivativedivides | \(\frac {\frac {\sin \left (f x +e \right ) \sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}}{2}+\frac {a \ln \left (\sqrt {b}\, \sin \left (f x +e \right )+\sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}\right )}{2 \sqrt {b}}-\frac {\sin \left (f x +e \right ) {\left (a +b \left (\sin ^{2}\left (f x +e \right )\right )\right )}^{\frac {3}{2}}}{4 b}+\frac {a \left (\frac {\sin \left (f x +e \right ) \sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}}{2}+\frac {a \ln \left (\sqrt {b}\, \sin \left (f x +e \right )+\sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}\right )}{2 \sqrt {b}}\right )}{4 b}}{f}\) | \(146\) |
default | \(\frac {\frac {\sin \left (f x +e \right ) \sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}}{2}+\frac {a \ln \left (\sqrt {b}\, \sin \left (f x +e \right )+\sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}\right )}{2 \sqrt {b}}-\frac {\sin \left (f x +e \right ) {\left (a +b \left (\sin ^{2}\left (f x +e \right )\right )\right )}^{\frac {3}{2}}}{4 b}+\frac {a \left (\frac {\sin \left (f x +e \right ) \sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}}{2}+\frac {a \ln \left (\sqrt {b}\, \sin \left (f x +e \right )+\sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}\right )}{2 \sqrt {b}}\right )}{4 b}}{f}\) | \(146\) |
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Time = 0.59 (sec) , antiderivative size = 511, normalized size of antiderivative = 4.37 \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\left [\frac {{\left (a^{2} + 4 \, a b\right )} \sqrt {b} \log \left (128 \, b^{4} \cos \left (f x + e\right )^{8} - 256 \, {\left (a b^{3} + 2 \, b^{4}\right )} \cos \left (f x + e\right )^{6} + 32 \, {\left (5 \, a^{2} b^{2} + 24 \, a b^{3} + 24 \, b^{4}\right )} \cos \left (f x + e\right )^{4} + a^{4} + 32 \, a^{3} b + 160 \, a^{2} b^{2} + 256 \, a b^{3} + 128 \, b^{4} - 32 \, {\left (a^{3} b + 10 \, a^{2} b^{2} + 24 \, a b^{3} + 16 \, b^{4}\right )} \cos \left (f x + e\right )^{2} - 8 \, {\left (16 \, b^{3} \cos \left (f x + e\right )^{6} - 24 \, {\left (a b^{2} + 2 \, b^{3}\right )} \cos \left (f x + e\right )^{4} - a^{3} - 10 \, a^{2} b - 24 \, a b^{2} - 16 \, b^{3} + 2 \, {\left (5 \, a^{2} b + 24 \, a b^{2} + 24 \, b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {-b \cos \left (f x + e\right )^{2} + a + b} \sqrt {b} \sin \left (f x + e\right )\right ) + 8 \, {\left (2 \, b^{2} \cos \left (f x + e\right )^{2} - a b + 2 \, b^{2}\right )} \sqrt {-b \cos \left (f x + e\right )^{2} + a + b} \sin \left (f x + e\right )}{64 \, b^{2} f}, -\frac {{\left (a^{2} + 4 \, a b\right )} \sqrt {-b} \arctan \left (\frac {{\left (8 \, b^{2} \cos \left (f x + e\right )^{4} - 8 \, {\left (a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + a^{2} + 8 \, a b + 8 \, b^{2}\right )} \sqrt {-b \cos \left (f x + e\right )^{2} + a + b} \sqrt {-b}}{4 \, {\left (2 \, b^{3} \cos \left (f x + e\right )^{4} + a^{2} b + 3 \, a b^{2} + 2 \, b^{3} - {\left (3 \, a b^{2} + 4 \, b^{3}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}\right ) - 4 \, {\left (2 \, b^{2} \cos \left (f x + e\right )^{2} - a b + 2 \, b^{2}\right )} \sqrt {-b \cos \left (f x + e\right )^{2} + a + b} \sin \left (f x + e\right )}{32 \, b^{2} f}\right ] \]
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Timed out. \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\text {Timed out} \]
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Time = 0.28 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.02 \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\frac {\frac {a^{2} \operatorname {arsinh}\left (\frac {b \sin \left (f x + e\right )}{\sqrt {a b}}\right )}{b^{\frac {3}{2}}} + \frac {4 \, a \operatorname {arsinh}\left (\frac {b \sin \left (f x + e\right )}{\sqrt {a b}}\right )}{\sqrt {b}} + 4 \, \sqrt {b \sin \left (f x + e\right )^{2} + a} \sin \left (f x + e\right ) - \frac {2 \, {\left (b \sin \left (f x + e\right )^{2} + a\right )}^{\frac {3}{2}} \sin \left (f x + e\right )}{b} + \frac {\sqrt {b \sin \left (f x + e\right )^{2} + a} a \sin \left (f x + e\right )}{b}}{8 \, f} \]
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\[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\int { \sqrt {b \sin \left (f x + e\right )^{2} + a} \cos \left (f x + e\right )^{3} \,d x } \]
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Timed out. \[ \int \cos ^3(e+f x) \sqrt {a+b \sin ^2(e+f x)} \, dx=\int {\cos \left (e+f\,x\right )}^3\,\sqrt {b\,{\sin \left (e+f\,x\right )}^2+a} \,d x \]
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